Home Physics Work, Energy, Power and Collision Conservation of Energy and Momentum A free body of mass 8 kg is travelling at 2 …
Physics Work, Energy, Power and Collision Conservation of Energy and Momentum MCQ (Single Correct)

A free body of mass 8 kg is travelling at 2 meter per second in a straight line. At a certain instant, the body splits into two equal parts due to internal explosion which releases 16 joules of energy. Neither part leaves the original line of motion finally

A
Both parts continue to move in the same direction as that of the original body
B
One part comes to rest and the other moves in the same direction as that of the original body
C
One part comes to rest and the other moves in the direction opposite to that of the original body
D
One part moves in the same direction and the other in the direction opposite to that of the original body

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Text Solution

Verified by Experts
The correct answer is:
B

As the body splits into two equal parts due to internal explosion therefore momentum of system remains

conserved

i.e. ⇒ ⇒ …(i)

By the law of conservation of energy

Initial kinetic energy + Energy released due to explosion

= Final kinetic energy of the system

⇒ ⇒

⇒ ⇒ …(ii)

By solving eq. (i) and (ii) we get and

i.e. one part comes to rest and other moves in the same direction as that of original body.

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